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2.8x^2-11.4x+7.6=0
a = 2.8; b = -11.4; c = +7.6;
Δ = b2-4ac
Δ = -11.42-4·2.8·7.6
Δ = 44.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.4)-\sqrt{44.84}}{2*2.8}=\frac{11.4-\sqrt{44.84}}{5.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.4)+\sqrt{44.84}}{2*2.8}=\frac{11.4+\sqrt{44.84}}{5.6} $
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